(x+4)(x^2-x+3)=0

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Solution for (x+4)(x^2-x+3)=0 equation: 


Simplifying
(x + 4)(x2 + -1x + 3) = 0

Reorder the terms:
(4 + x)(x2 + -1x + 3) = 0

Reorder the terms:
(4 + x)(3 + -1x + x2) = 0

Multiply (4 + x) * (3 + -1x + x2)
(4(3 + -1x + x2) + x(3 + -1x + x2)) = 0
((3 * 4 + -1x * 4 + x2 * 4) + x(3 + -1x + x2)) = 0
((12 + -4x + 4x2) + x(3 + -1x + x2)) = 0
(12 + -4x + 4x2 + (3 * x + -1x * x + x2 * x)) = 0
(12 + -4x + 4x2 + (3x + -1x2 + x3)) = 0

Reorder the terms:
(12 + -4x + 3x + 4x2 + -1x2 + x3) = 0

Combine like terms: -4x + 3x = -1x
(12 + -1x + 4x2 + -1x2 + x3) = 0

Combine like terms: 4x2 + -1x2 = 3x2
(12 + -1x + 3x2 + x3) = 0

Solving
12 + -1x + 3x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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